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5/24/2010 12:42:56 AM
Title: popup window position
Hi All,
I have a popup window, by default i given a center pop up in my appliation, but i want top right of the application. How to give? please help me..
Thanks in advance,
K.V.Ramakrishna
1
Using flex with Actionscript 3.0
To position you popup window you can add it to some container and place that container at any position.
To position you popup window you can add it to some container and place that container at any position.
//here myTitleWindow is my TitleWindow that I am adding as popup and popContainer is my Vbox which is placed at x=0. So my popup window is also placed at x.
mx.managers.PopUpManager.addPopUp(myTitleWindow, popContainer, true);
2
you can position the popUpWIndow to center using PopUpManager.createPopUp(yourPopUp);
3
4
check this sample to position popup anywhere in application using flex
<?xml version="1.0" encoding="utf-8"?>
<mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" width="700" height="400">
<mx:Script>
<![CDATA[
import mx.managers.PopUpManager;
import mx.containers.TitleWindow;
private function createPopup():void{
var tw:TitleWindow = new TitleWindow();
tw.title = "My Title";
mx.managers.PopUpManager.addPopUp(pnl, popContainer, true);
}
private function removePopup():void{
PopUpManager.removePopUp(pnl);
}
]]>
</mx:Script>
<mx:Button x="32" y="37" label="Create Popup" click="createPopup()"/>
<mx:Button x="143" y="37" label="Remove Popup" click="removePopup()"/>
<mx:VBox x="0" y="50" id="popContainer">
</mx:VBox>
<mx:TitleWindow x="143" y="98" id="pnl" backgroundColor="#FF5B5B" dropShadowEnabled="true" shadowDirection="right" shadowDistance="10" backgroundAlpha="1" borderStyle="solid">
<mx:FormItem label=" My pop Up Content">
<mx:Button label="Button"/>
</mx:FormItem>
</mx:TitleWindow>
</mx:Application>
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